لطلاب السنة اولى ثانوي
اريد حل التمرين ص21 رقم44 من كتاب الرياضيات للسنة اولى ثانوي
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: M 4%E. $%%ED
AM2 = AB 2 + BM 2 : +,*- ABM >?+B *
AM2 = 9 + ( BC – MC ) 2 : t,X.
AM2 = 9 + ( 5 – MC ) 2 : :<=
35
DM2 = DC 2 + MC 2 : +,*- DCM >?+B . *
DM2 = 16 + MC 2 : t,X.
AM2 = DM 2 : :+; <= 7B. <= AM = DM
"*
9 + ( 5 – MC ) 2 = 16 + MC 2 : :G ,E* …J.
: t,X. 9 + 25 – 10MC + MC 2 = 16 + MC 2 : ’G 10
MC = 18
. MB = 3,2 Cm : ’G MB = 5 – 1,8 : t%8. . MC = 1,8 Cm : ’G
: 22
:’OC5 !T ( 1
. x < y +6+F . t)^ y . !%q62 ZO8 x ZOvV
2 ( x + y ) = 10 —. x y = 6 :"%
x + y = 5 —. x y = 6 : :<=
y = 5 – x —. x y = 6 : t%8.
y = 5 – x —. x (5-x)=6 : t,X.
4%V+ 4‚A- $X 4H+EX J . x2 + 5 x – 6 = 0 : :<=
AM2 = AB 2 + BM 2 : +,*- ABM >?+B *
AM2 = 9 + ( BC – MC ) 2 : t,X.
AM2 = 9 + ( 5 – MC ) 2 : :<=
35
DM2 = DC 2 + MC 2 : +,*- DCM >?+B . *
DM2 = 16 + MC 2 : t,X.
AM2 = DM 2 : :+; <= 7B. <= AM = DM
"*9 + ( 5 – MC ) 2 = 16 + MC 2 : :G ,E* …J.
: t,X. 9 + 25 – 10MC + MC 2 = 16 + MC 2 : ’G 10
MC = 18
. MB = 3,2 Cm : ’G MB = 5 – 1,8 : t%8. . MC = 1,8 Cm : ’G
: 22
:’OC5 !T ( 1
. x < y +6+F . t)^ y . !%q62 ZO8 x ZOvV
2 ( x + y ) = 10 —. x y = 6 :
"%x + y = 5 —. x y = 6 : :<=
y = 5 – x —. x y = 6 : t%8.
y = 5 – x —. x (5-x)=6 : t,X.
4%V+ 4‚A- $X 4H+EX J . x2 + 5 x – 6 = 0 : :<=
= b2 – 4ac = 52 – 4 (-1)(-6) = 1 : +,*-
1 :+J $%3 4H+E t,X.
x = -b – = – 5 -1 = 3
2a 2 (-1)
—.
2
x = -b + = – 5 +1 = 2
2a 2 (-1)
( x < y :[Z)OX ) y = 2 : :+ x = 3 +
y = 3 : :+ x = 2 +
. 2 Cm tO8 —. 3 Cm t)^ %3 !%q62X -‚)* t,X.
